Math: Geometry and Trigonometry

SAT Question of the Day for October 6, 2026

In triangle PQRPQR, point SS lies on PQ‾\overline{PQ} and point TT lies on QR‾\overline{QR} such that ST‾\overline{ST} is parallel to PR‾\overline{PR}. If QS=14QS = 14, SP=21SP = 21, and ST=18ST = 18, what is the length of PR‾\overline{PR}?

Correct answer: 45

Explanation

Since ST‾\overline{ST} is parallel to PR‾\overline{PR}, triangles QSTQST and QPRQPR are similar by the AA similarity criterion. The ratio of corresponding sides equals QSQP=1414+21=1435=25\frac{QS}{QP} = \frac{14}{14 + 21} = \frac{14}{35} = \frac{2}{5}. Therefore STPR=25\frac{ST}{PR} = \frac{2}{5}, which gives PR=18×52=45PR = 18 \times \frac{5}{2} = 45. A common error is using the ratio QSSP=1421=23\frac{QS}{SP} = \frac{14}{21} = \frac{2}{3} instead of QSQP=25\frac{QS}{QP} = \frac{2}{5}, which would incorrectly yield PR=18×32=27PR = 18 \times \frac{3}{2} = 27. Another error is applying the ratio in the wrong direction, computing 18×25=7.218 \times \frac{2}{5} = 7.2 instead of dividing.

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